Tolong Bantu Jawab kaka
Jawab:
limit
1) lim x->- 4 ∛(5x² -6x + 1)
substitusi x = - 4
limit = ∛{5(-4)² -6(-4) + 1} = ∛(80+24+1)=∛105
2) bentuk 0/0.
[tex]\sf lim_{x\to -2} ~\dfrac{x^2 - 9x-22}{x^2 - 4}[/tex]
faktorkan
[tex]\sf lim_{x\to -2} ~\dfrac{( x+ 2)(x -11)}{( x+2)(x -2)}[/tex]
[tex]\sf lim_{x\to -2} ~\dfrac{x -11}{x -2}[/tex]
substitusi x = - 2
[tex]\sf lim_{x\to -2} ~\dfrac{-2 -11}{-2 -2}=\dfrac{-13}{-4} = \dfrac{13}{4}[/tex]
3) substitusi nilai x
[tex]\sf lim_{x\to~-4}~\dfrac{4+ x}{\sqrt{x^2 +9}}[/tex]
substitusi x = - 4
[tex]\sf lim_{x\to~-4}~\dfrac{4 -4}{\sqrt{4^2 +9}} = \dfrac{0}{5} = 0[/tex]
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